Article ID | Journal | Published Year | Pages | File Type |
---|---|---|---|---|
10997885 | Comptes Rendus Mathematique | 2016 | 4 Pages |
Abstract
Let d(n) and dâ(n) be the numbers of divisors and the numbers of unitary divisors of the integer n, and let S(x)=ânâ¤xD(n)=ânâ¤xd(n)dâ(n)(xâ¥1). A divisor d of a integer n is called unitary if it is prime with nd. In this paper, we prove that S(x)â¼Ax(xâ+â), where A=Ï26âp(1â12p2+12p3)=1.4276565â¯, and for all xâ¥1, S(x)=Ax+R(x) such that|R(x)|â¤32ζ(32)x12+54ζ(23)x13+O(x15).
Related Topics
Physical Sciences and Engineering
Mathematics
Mathematics (General)
Authors
Abdallah Derbal, Meselem Karras,