| Article ID | Journal | Published Year | Pages | File Type |
|---|---|---|---|---|
| 1326557 | Journal of Organometallic Chemistry | 2009 | 8 Pages |
When RhCl3 · 3H2O was treated with an excess of Te(CH2SiMe3)2, a mononuclear mer-[RhCl3{Te(CH2SiMe3)2}3] (1) was observed as the main product. By reducing the metal-to-ligand molar ratio, dinuclear [Rh2(μ-Cl)2Cl4{Te(CH2SiMe3)2}4] (2) was obtained in addition to 1. Further reduction of the metal-to-ligand ratio resulted in the formation of [Rh2(μ-Cl)2Cl4(OHCH2CH3){Te(CH2SiMe3)2}3] (3). The treatment of mer-[RhCl3(SMePh)3] (4) with two equivalents of Te(CH2SiMe3)2 affords a mixture of mer-[RhCl3{Te(CH2SiMe3)2}3] (1) and mer-[RhCl3{Te(CH2SiMe3)2}2(SMePh)] (5). All complexes 1–4 and 5 · ½EtOH were characterized by X-ray crystallography and 125Te NMR spectroscopy, where appropriate. The definite assignment of the 125Te chemical shifts enabled a plausible discussion of the assignment of some unknown resonances that were observed in the NMR spectra.
Graphical abstractThe treatment of RhCl3 · 3H2O with Te(CH2SiMe3)2 afforded a mononuclear mer-[RhCl3{Te(CH2SiMe3)2}3] (1), dinuclear [Rh2(μ-Cl)2Cl4{Te(CH2SiMe3)2}4] (2), and [Rh2(μ-Cl)2Cl4(OHCH2CH3){Te(CH2SiMe3)2}3] (3) depending on the molar ratio of the reactants.Figure optionsDownload full-size imageDownload as PowerPoint slide
