| Article ID | Journal | Published Year | Pages | File Type |
|---|---|---|---|---|
| 4582504 | Expositiones Mathematicae | 2009 | 5 Pages |
Abstract
The solution of the linear operator equation:An-1X+An-2XB+⋯+AXBn-2+XBn-1=YAn-1X+An-2XB+⋯+AXBn-2+XBn-1=Y is given by X=((sinπ/n)/π)∫0∞(t+An)-1Y(t+Bn)-1t1/ndt if the spectra of A and B are in the sector {z:z≠0,-π/n
Keywords
Related Topics
Physical Sciences and Engineering
Mathematics
Algebra and Number Theory
Authors
Rajendra Bhatia, Mitsuru Uchiyama,