Article ID Journal Published Year Pages File Type
4590790 Journal of Functional Analysis 2011 21 Pages PDF
Abstract
Consider an operator T:C2(R)→C(R) and isotropic maps A1,A2:C1(R)→C(R) such that the functional equationT(f∘g)=(Tf)∘g⋅A1g+(A2f)∘g⋅Tg;f,g∈C2(R) is satisfied on C2(R). The equation models the chain rule for the second derivative, in which case A1g=g′2 and A2f=f′. We show under mild non-degeneracy conditions - which imply that A1 and A2 are very different from T - that A1 and A2 must be of the very restricted form A1f=f′⋅A2f, A2f=|f′|p or sgn(f′)|f′|p, with p⩾1, and that any solution operator T has the formTf(x)=cA2(f(x))f′(x)f″(x)+(H(f(x))f′(x)−H(x))A2(f(x)),x∈R for some constant c∈R and some continuous function H. Conversely, any such map T satisfies the functional equation. Under some natural normalization condition, the only solution of the functional equation is Tf=f″ which means that the composition rule with some normalization condition characterizes the second derivative. If c=0, T does not depend on the second derivative. In this case, there are further solutions of the functional equation which we determine, too.
Related Topics
Physical Sciences and Engineering Mathematics Algebra and Number Theory
Authors
, ,