Article ID | Journal | Published Year | Pages | File Type |
---|---|---|---|---|
4615256 | Journal of Mathematical Analysis and Applications | 2015 | 12 Pages |
Abstract
Let ζn(z):=∑k=1n1kz, z=x+iyz=x+iy, be the n th partial sum of the Riemann zeta function and aζn(z):=inf{ℜz:ζn(z)=0}aζn(z):=inf{ℜz:ζn(z)=0}. In this paper we prove that aζn(z)=−log2log(n−1n−2)+Δn, n>2n>2, with limsupn→∞limsupn→∞ |Δn|≤log2|Δn|≤log2.
Related Topics
Physical Sciences and Engineering
Mathematics
Analysis
Authors
G. Mora,