Article ID Journal Published Year Pages File Type
4648408 Discrete Mathematics 2009 5 Pages PDF
Abstract

We prove that in every cyclic cycle-decomposition of K2n−IK2n−I (the cocktail party graph of order 2n2n) the number of cycle-orbits of odd length must have the same parity of n(n−1)/2n(n−1)/2. This gives, as corollaries, some useful non-existence results one of which allows to determine when the two table Oberwolfach Problem OP(3,2ℓ)OP(3,2ℓ) admits a 1-rotational solution.

Related Topics
Physical Sciences and Engineering Mathematics Discrete Mathematics and Combinatorics
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