Article ID | Journal | Published Year | Pages | File Type |
---|---|---|---|---|
6414624 | Journal of Algebra | 2014 | 14 Pages |
The coprime commutators γjâ and δjâ were recently introduced as a tool to study properties of finite groups that can be expressed in terms of commutators of elements of coprime orders. Every element of a finite group G is both a γ1â-commutator and a δ0â-commutator. Now let j⩾2 and let X be the set of all elements of G that are powers of γjâ1â-commutators. An element g is a γjâ-commutator if there exist aâX and bâG such that g=[a,b] and (|a|,|b|)=1. For j⩾1 let Y be the set of all elements of G that are powers of δjâ1â-commutators. An element g is a δjâ-commutator if there exist a,bâY such that g=[a,b] and (|a|,|b|)=1. The subgroups of G generated by all γjâ-commutators and all δjâ-commutators are denoted by γjâ(G) and δjâ(G), respectively. For every j⩾2 the subgroup γjâ(G) is precisely the last term γâ(G) of the lower central series of G, while for every j⩾1 the subgroup δjâ(G) is precisely the last term of the lower central series of δjâ1â(G), that is, δjâ(G)=γâ(δjâ1â(G)).In the present paper we prove that if G possesses m cyclic subgroups whose union contains all γjâ-commutators of G, then γjâ(G) contains a subgroup Î, of m-bounded order, which is normal in G and has the property that γjâ(G)/Î is cyclic. If j⩾2 and G possesses m cyclic subgroups whose union contains all δjâ-commutators of G, then the order of δjâ(G) is m-bounded.