کد مقاله | کد نشریه | سال انتشار | مقاله انگلیسی | نسخه تمام متن |
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4656825 | 1632984 | 2014 | 33 صفحه PDF | دانلود رایگان |
In this paper, we prove the following theorem, which is motivated by two different contexts independently, namely graph theory and combinatorial optimization. Given a circuit graph (which is obtained from a 3-connected planar graph by deleting one vertex) with n vertices, there is a spanning closed walk W of length at most 4(n−1)/34(n−1)/3 such that each edge is used by W at most twice.Our proof is constructive (and purely combinatorial) in the sense that there is an O(n2)O(n2)-time algorithm to construct such a walk in a given 3-connected planar graph. We shall construct an example that shows that the upper bound 4(n−1)/34(n−1)/3 is essentially tight. We also point out that 2-connected planar graphs may not have such a walk, as K2,n−2K2,n−2 shows.
Journal: Journal of Combinatorial Theory, Series B - Volume 109, November 2014, Pages 1–33